C++读取本地时间,用数码形式输出

这个要是用Qt或者MFC等图形库估计很容易就实现了,可是用字符界面还是很麻烦的,具体看代码

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#include <iostream>
#include <string>
#include <ctime>
using namespace std;
string num[5][11] = {"****", " *", "****", "****", "* *", "****", "****", "****", "****", "****", " ",
"* *", " *", " *", " *", "* *", "* ", "* ", " *", "* *", "* *", " * ",
"* *", " *", "****", "****", "****", "****", "****", " *", "****", "****", " ",
"* *", " *", "* ", " *", " *", " *", "* *", " *", "* *", " *", " * ",
"****", " *", "****", "****", " *", "****", "****", " *", "****", "****", " "};

int main()
{
int i,j;
/*for(i= 0;i <a href="http://grandruby.co.uk/tips-on-choosing-the-best-poker-rooms">online casinos</a> < 10; i ) {
for(j = 0; j < 10; j ) {
cout << num[i][j] << " ";
}
cout << endl;
}
cout << endl << endl;*/

time_t t= time(0);
tm *curtime = localtime(&t);

int hour = curtime->tm_hour;
int min = curtime->tm_min;
int sec = curtime->tm_sec;
cout << hour << ":" << min << ":" << sec << endl;
cout << endl;

int timeArray[8];
timeArray[0] = hour / 10;
timeArray[1] = hour % 10;
timeArray[2] = 10;
timeArray[3] = min / 10;
timeArray[4] = min % 10;
timeArray[5] = 10;
timeArray[6] = sec / 10;
timeArray[7] = sec % 10;

for(i = 0; i < 5; i ) {
for(j = 0; j < 8; j ) {
cout << num[i][timeArray[j]] << " ";
}
cout << endl;
}
return 0;
}

这里用到两个函数time和localtime,两个函数包含与time.h里面
time_t time( time_t time );
功能: 函数返回当前时间,如果发生错误返回零。如果给定参数time ,那么当前时间存储到参数time中。
struct tm
gmtime( const time_t *time );
功能:函数返回给定的统一世界时间(通常是格林威治时间),如果系统不支持统一世界时间系统返回NULL。

PS:C语言果然博大精深….

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